What is the average kinetic energy of 1 mole of a gas at -32 degrees Celsius? (R = 8.314 J/K-mol)

$$3.01~x~10^3 J$$$$-3.99~x~10^2 J$$$$6.01~x~10^3 J$$$$4.32~x~10^3 J$$

Question

What is the average kinetic energy of 1 mole of a gas at -32 degrees Celsius? (R = 8.314 J/K-mol)
		
$$3.01~x~10^3 J$$$$-3.99~x~10^2 J$$$$6.01~x~10^3 J$$$$4.32~x~10^3 J$$

rhondasommer · Answer

I guessed and got it wrong :/

math&ing001 · Answer

Use the formula : $$KE_{avg}=\frac{3}{2}RT $$
Don't forget to turn the temperature to kelvin ;]

math&ing001 · Answer

@RhondaSommer you wanna try again ?

rhondasommer · Answer

im sooo confused by that formula

math&ing001 · Answer

KE stands for Kinetic Energie (what you're looking for :P)
T stands for temprature, and you already got R (the universal gas constant)
Still anything confusing you ?

rhondasommer · Answer

KE = 3/2 * n * R T?

rhondasommer · Answer

KE = 3/2 * 1 * 8.314 * (-32 +  273.15)

math&ing001 · Answer

Why "n" ? That's kinetic energie per mol..

math&ing001 · Answer

Yep, looks correct !