I have this question in vector calculus. pls help I tried everything I know....

Question

sweetdanny · Answer

pls check attachment: To find surface integral ????

sweetdanny · Answer

I will give a medal and best feedback :)

kainui · Answer

Try drawing a picture of the lines $y=3-z^2$ , $x=0$ and $z=5$

sweetdanny · Answer

inverted parabola on yz plane pushed 3units up

sweetdanny · Answer

I used double integral(F.ds)
but boundaries for x??? I cant tell

kainui · Answer

Strange. It seems like there's no lower bound on z and no upper bound on x. But the way they've written it is weird, I wonder if they're just lazy. If you look carefully they have NOT written:

$$0 \le x$$ and $$z\le 5$$
It looks like they've confusingly written
$$0 \le x, z \le 5$$

Is that supposed to mean
$$0 \le x\le 5$$ and$$0 \le z \le 5$$?
That would definitely fix the problem with there not being any bounds but seriously I have no idea why someone would do something so idiotic in writing a question up like this... It's confusing enough as it is. Ugh

kainui · Answer

The other alternative is just to take it to mean it's an unbounded integral so it's like an infinite sheet perhaps.

kainui · Answer

|dw:1461466271295:dw|