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Mathematics 9 Online
OpenStudy (pphalke):

assistance please

OpenStudy (pphalke):

OpenStudy (latinc):

lets start with standard form (y-b) =m(x-a)

OpenStudy (pphalke):

how do i do that?

OpenStudy (latinc):

lets find the slope first (y2-y1) /(x2-x1)

OpenStudy (pphalke):

4/3-5/3 _________ 1/3-(-2/3)

OpenStudy (pphalke):

i dont know how to solve this type

OpenStudy (latinc):

yes, so just subtract the top numbers in each of the fractions

OpenStudy (pphalke):

i don know how

OpenStudy (latinc):

so ---> (4-5)/3 is your (y) value and (1-2)/3 is your (x) value

OpenStudy (latinc):

how we doing

OpenStudy (pphalke):

this is confusing its (4-5)/3? we have to solve first

OpenStudy (pphalke):

strange decimal -0.3?

OpenStudy (latinc):

:( don't divide the solution remember that the top is a (y) value and your bottom is a (x) value

OpenStudy (pphalke):

this is confusing i dont know this. i never subtracted fractions this way

OpenStudy (latinc):

(-1/3)/(-1/3) = (-1/3, -1/3) ----> (x,y)

OpenStudy (latinc):

show me the solution to the top

OpenStudy (pphalke):

i dont know how for that one

OpenStudy (latinc):

top is (4-5)/3

OpenStudy (latinc):

have you ever worked with negative numbers

OpenStudy (pphalke):

nope

OpenStudy (latinc):

Oooo. try this webpage to help you catch up in math KhanAcademy.com

OpenStudy (pphalke):

i did that please help me get the answer

OpenStudy (latinc):

my user name is mrc511 I can help you there better because there are an infinite number of problem to try

OpenStudy (latinc):

will this are your x and y values (-1/3, -1/3); since both top and bottom are the same your slope is 1 or m = 1 in y=mx+b, so use y=mx+b to find b by simple inputting a y and x value form the original question

OpenStudy (pphalke):

how do i put it into slope intercept form

OpenStudy (latinc):

slope intercept is y = mx + b; so 5/3 = 1(-2/3) +b ---> find b

OpenStudy (latinc):

5/3 + 2/3 = b

OpenStudy (latinc):

then you can check your answer by inputting your other set of points in and you should get the same (b) value

OpenStudy (pphalke):

isnt that 7/3?

OpenStudy (pphalke):

how do i put it into the form of y=mx+b i found b

OpenStudy (latinc):

input your slope which is m and then input your b value so y =1x +(your b value)

OpenStudy (pphalke):

y=1x+7/3?

OpenStudy (latinc):

yes :)

OpenStudy (pphalke):

its not correct according to the homework

OpenStudy (latinc):

you only answers question a right

OpenStudy (pphalke):

:(((

OpenStudy (latinc):

I found the issue hold on

OpenStudy (pphalke):

one more chance or it will switch to a nther one

OpenStudy (latinc):

your slope should be -1/3 because (1-(-2)) =3

OpenStudy (latinc):

so lets rework the slope and proof

OpenStudy (latinc):

y = -1/3x + 4/3, for the first point; now lets proof that the equation is correct by input the second point and solving for b

OpenStudy (pphalke):

how do i do that

OpenStudy (latinc):

4/3 = -1/3(1/3) +b

OpenStudy (pphalke):

my calc wont allow this entry it comes as a weird decimal

OpenStudy (latinc):

b = 13/9 but try it without your calculator

OpenStudy (latinc):

4/3 = -1/9 + b

OpenStudy (pphalke):

i get 1.4 even without calc

OpenStudy (latinc):

don't solve final fraction you don't have to

OpenStudy (pphalke):

wouldnt it be y=1.4x+1/3 or ??

OpenStudy (latinc):

if you solve the fraction you'd get a repeating 1.4444444444444

OpenStudy (latinc):

no, 13/9 is your b value and -1/3 is your m value

OpenStudy (latinc):

y = -1/3x + 13/9 , where did you get a positive 1/3?

OpenStudy (pphalke):

lemme enter that remember it says final check so if i blow it it iwill change

OpenStudy (pphalke):

if theres any change let me know now before i enter @latinC

OpenStudy (pphalke):

is this the correct answer, i have one chance i cant blow it

OpenStudy (latinc):

yes,

OpenStudy (pphalke):

its asking for standard for so what would it be in standard form

OpenStudy (latinc):

standard form is (y-b) = m(x-a) ; m = your slope

OpenStudy (pphalke):

so 13/9 would be m(-1/3-a)?? i dont know how to note in st form standard

OpenStudy (latinc):

sorry standard form is Ax+By = C

OpenStudy (latinc):

so lets start with y =mx +b or y = -1/3x + 13/9

OpenStudy (latinc):

now lets multiply (3)y = (-1/3x +13/9)(3)

OpenStudy (pphalke):

3y= i dont know the rest

OpenStudy (latinc):

yes, 3y = (-3/3x + 39/9)

OpenStudy (latinc):

now lets multiply again (9)3y = (-1x + 39/9)(9)

OpenStudy (latinc):

27y = -9x + 39

OpenStudy (pphalke):

is that in standard form?

OpenStudy (latinc):

no, remember Ax+By = C

OpenStudy (pphalke):

-9x+27y=39

OpenStudy (latinc):

no

OpenStudy (latinc):

almost

OpenStudy (pphalke):

how then?

OpenStudy (latinc):

27y =-9x+39, since we want the -9x on the other side we need to add 9x to both sides. remember that algebra is all about balance

OpenStudy (pphalke):

u mean 9x to 27y and 39??

OpenStudy (latinc):

9x +27y = -9x +9x +39, solve this

OpenStudy (pphalke):

hmm i get 9x+27y=39??

OpenStudy (latinc):

standard form is Ax+By = C

OpenStudy (pphalke):

idk :(

OpenStudy (latinc):

yes you had it right 9x+27y =39

OpenStudy (pphalke):

im afraid if i enter it will be wrong

OpenStudy (latinc):

check it ,

OpenStudy (latinc):

by reversing the processes

OpenStudy (pphalke):

its says wrong still i have one more chance now

OpenStudy (latinc):

27y = -9x +39 ---> y = -9/27x + 39/27---> y = -1/3x +13/9

OpenStudy (agent0smith):

9x+27y =39 Standard form means Ax+By=C but simplified. These are all multiples of 3

OpenStudy (pphalke):

it says thats wrong grrrrr

OpenStudy (latinc):

he means divide everything by 3

OpenStudy (pphalke):

x+3y=4??? or as i got 3x+9y=12?? which one

OpenStudy (latinc):

9x+27y = 39 -----> 3x +9y = 13

OpenStudy (pphalke):

do i need to do anything more?

OpenStudy (latinc):

can't

OpenStudy (pphalke):

i guess thats it then lemme enter it and see

OpenStudy (pphalke):

its correct thank you both :)

OpenStudy (latinc):

yea thanks agentOsmith

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