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OpenStudy (pphalke):
OpenStudy (latinc):
lets start with standard form (y-b) =m(x-a)
OpenStudy (pphalke):
how do i do that?
OpenStudy (latinc):
lets find the slope first (y2-y1) /(x2-x1)
OpenStudy (pphalke):
4/3-5/3
_________
1/3-(-2/3)
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OpenStudy (pphalke):
i dont know how to solve this type
OpenStudy (latinc):
yes, so just subtract the top numbers in each of the fractions
OpenStudy (pphalke):
i don know how
OpenStudy (latinc):
so ---> (4-5)/3 is your (y) value and (1-2)/3 is your (x) value
OpenStudy (latinc):
how we doing
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OpenStudy (pphalke):
this is confusing its (4-5)/3? we have to solve first
OpenStudy (pphalke):
strange decimal -0.3?
OpenStudy (latinc):
:( don't divide the solution remember that the top is a (y) value and your bottom is a (x) value
OpenStudy (pphalke):
this is confusing i dont know this. i never subtracted fractions this way
OpenStudy (latinc):
(-1/3)/(-1/3) = (-1/3, -1/3) ----> (x,y)
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OpenStudy (latinc):
show me the solution to the top
OpenStudy (pphalke):
i dont know how for that one
OpenStudy (latinc):
top is (4-5)/3
OpenStudy (latinc):
have you ever worked with negative numbers
OpenStudy (pphalke):
nope
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OpenStudy (latinc):
Oooo. try this webpage to help you catch up in math KhanAcademy.com
OpenStudy (pphalke):
i did that
please help me get the answer
OpenStudy (latinc):
my user name is mrc511 I can help you there better because there are an infinite number of problem to try
OpenStudy (latinc):
will this are your x and y values (-1/3, -1/3); since both top and bottom are the same your slope is 1 or m = 1 in y=mx+b, so use y=mx+b to find b by simple inputting a y and x value form the original question
OpenStudy (pphalke):
how do i put it into slope intercept form
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OpenStudy (latinc):
slope intercept is y = mx + b; so 5/3 = 1(-2/3) +b ---> find b
OpenStudy (latinc):
5/3 + 2/3 = b
OpenStudy (latinc):
then you can check your answer by inputting your other set of points in and you should get the same (b) value
OpenStudy (pphalke):
isnt that 7/3?
OpenStudy (pphalke):
how do i put it into the form of y=mx+b i found b
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OpenStudy (latinc):
input your slope which is m and then input your b value so y =1x +(your b value)
OpenStudy (pphalke):
y=1x+7/3?
OpenStudy (latinc):
yes :)
OpenStudy (pphalke):
its not correct according to the homework
OpenStudy (latinc):
you only answers question a right
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OpenStudy (pphalke):
:(((
OpenStudy (latinc):
I found the issue hold on
OpenStudy (pphalke):
one more chance or it will switch to a nther one
OpenStudy (latinc):
your slope should be -1/3 because (1-(-2)) =3
OpenStudy (latinc):
so lets rework the slope and proof
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OpenStudy (latinc):
y = -1/3x + 4/3, for the first point; now lets proof that the equation is correct by input the second point and solving for b
OpenStudy (pphalke):
how do i do that
OpenStudy (latinc):
4/3 = -1/3(1/3) +b
OpenStudy (pphalke):
my calc wont allow this entry it comes as a weird decimal
OpenStudy (latinc):
b = 13/9 but try it without your calculator
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OpenStudy (latinc):
4/3 = -1/9 + b
OpenStudy (pphalke):
i get 1.4 even without calc
OpenStudy (latinc):
don't solve final fraction you don't have to
OpenStudy (pphalke):
wouldnt it be y=1.4x+1/3 or ??
OpenStudy (latinc):
if you solve the fraction you'd get a repeating 1.4444444444444
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OpenStudy (latinc):
no, 13/9 is your b value and -1/3 is your m value
OpenStudy (latinc):
y = -1/3x + 13/9 , where did you get a positive 1/3?
OpenStudy (pphalke):
lemme enter that remember it says final check so if i blow it it iwill change
OpenStudy (pphalke):
if theres any change let me know now before i enter @latinC
OpenStudy (pphalke):
is this the correct answer, i have one chance i cant blow it
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OpenStudy (latinc):
yes,
OpenStudy (pphalke):
its asking for standard for so what would it be in standard form
OpenStudy (latinc):
standard form is (y-b) = m(x-a) ; m = your slope
OpenStudy (pphalke):
so 13/9 would be m(-1/3-a)?? i dont know how to note in st form standard
OpenStudy (latinc):
sorry standard form is Ax+By = C
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OpenStudy (latinc):
so lets start with y =mx +b or y = -1/3x + 13/9
OpenStudy (latinc):
now lets multiply (3)y = (-1/3x +13/9)(3)
OpenStudy (pphalke):
3y= i dont know the rest
OpenStudy (latinc):
yes, 3y = (-3/3x + 39/9)
OpenStudy (latinc):
now lets multiply again (9)3y = (-1x + 39/9)(9)
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OpenStudy (latinc):
27y = -9x + 39
OpenStudy (pphalke):
is that in standard form?
OpenStudy (latinc):
no, remember Ax+By = C
OpenStudy (pphalke):
-9x+27y=39
OpenStudy (latinc):
no
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OpenStudy (latinc):
almost
OpenStudy (pphalke):
how then?
OpenStudy (latinc):
27y =-9x+39, since we want the -9x on the other side we need to add 9x to both sides. remember that algebra is all about balance
OpenStudy (pphalke):
u mean 9x to 27y and 39??
OpenStudy (latinc):
9x +27y = -9x +9x +39, solve this
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OpenStudy (pphalke):
hmm i get 9x+27y=39??
OpenStudy (latinc):
standard form is Ax+By = C
OpenStudy (pphalke):
idk :(
OpenStudy (latinc):
yes you had it right 9x+27y =39
OpenStudy (pphalke):
im afraid if i enter it will be wrong
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OpenStudy (latinc):
check it ,
OpenStudy (latinc):
by reversing the processes
OpenStudy (pphalke):
its says wrong still i have one more chance now
OpenStudy (latinc):
27y = -9x +39 ---> y = -9/27x + 39/27---> y = -1/3x +13/9
OpenStudy (agent0smith):
9x+27y =39
Standard form means Ax+By=C but simplified. These are all multiples of 3
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OpenStudy (pphalke):
it says thats wrong grrrrr
OpenStudy (latinc):
he means divide everything by 3
OpenStudy (pphalke):
x+3y=4??? or as i got 3x+9y=12?? which one
OpenStudy (latinc):
9x+27y = 39 -----> 3x +9y = 13
OpenStudy (pphalke):
do i need to do anything more?
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