Please check my work.

On an icy day, Sarah dropped her cell phone on the road near the top of a hill. The phone slid down the slippery street with an acceleration of 6.5 m/s2. The phone has a mass of 85 g.

Assuming the ice was frictionless, with what force was gravity pulling the phone down the hill?

A.0.83 N
B. 76 N
C. 13 N
D. 0.55 N

My work is this: 85/6.5=13.0, which i'm leaning as C, but I want to make sure I did the question correctly. Can someone confirm this?

Question

Please check my work.

On an icy day, Sarah dropped her cell phone on the road near the top of a hill. The phone slid down the slippery street with an acceleration of 6.5 m/s2. The phone has a mass of 85 g.

Assuming the ice was frictionless, with what force was gravity pulling the phone down the hill?

  A.0.83 N
  B. 76 N
  C. 13 N
  D. 0.55 N

My work is this: 85/6.5=13.0, which i'm leaning as C, but I want to make sure I did the question correctly. Can someone confirm this?

av0cad0 · Answer

Anyone?

pphalke · Answer

yes thats what i got so u are rigght

pphalke · Answer

did you get that right? i did it with calculator @av0cad0

agent0smith · Answer

Can you explain what you did? Because it made no sense to me, you divided mass by acceleration

agent0smith · Answer

Use net force = ma

you have acceleration and mass. Convert mass to kg.

scooby6363 · Answer

Like agentsmith said, according to Newton's Second Law 
Force = Mass * Acceleration
85 grams / 1000 = .085 kg (Mass is in kilograms)
(.085 kg)(6.5 m/s^2) = .5525 N

You probably should have posted this in the physics section.

av0cad0 · Answer

its too late now, it was late at night and i got it wrong.