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rebeccaxhawaii (rebeccaxhawaii):
Given the functions f(n ) = 11 and g(n ) = -2(n - 1), combine them to create an arithmetic sequence, an, and solve for the 31st term.
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ILovePuppiesLol (ilovepuppieslol):
noob, this is so easy
rebeccaxhawaii (rebeccaxhawaii):
says the one in alg 1 -.-
ILovePuppiesLol (ilovepuppieslol):
@Kainui help us please :)
OpenStudy (inkyvoyd):
noob, this is so easy
ILovePuppiesLol (ilovepuppieslol):
well said @inkyvoyd
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ILovePuppiesLol (ilovepuppieslol):
@jim_thompson5910 @Mehek14 please help us :(
jimthompson5910 (jim_thompson5910):
one way is to do
f(n) + g(n) = [11] + [-2(n-1)]
f(n) + g(n) = 11 - 2(n-1)
notice how 11 is the first term and -2 is the common difference
OpenStudy (kainui):
I have honestly no idea what you're expected to do
jimthompson5910 (jim_thompson5910):
you could also do f(n) - g(n), but that leads to a different common difference
rebeccaxhawaii (rebeccaxhawaii):
then plug 31 for n?
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ILovePuppiesLol (ilovepuppieslol):
wow my tags worked
rebeccaxhawaii (rebeccaxhawaii):
yes ty b
jimthompson5910 (jim_thompson5910):
`then plug 31 for n?` yes correct @rebeccaxhawaii
rebeccaxhawaii (rebeccaxhawaii):
okay so 11-2(31-1)
11-2(30)
11-60
f(n)+g(n)=-49??
jimthompson5910 (jim_thompson5910):
looks good
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rebeccaxhawaii (rebeccaxhawaii):
yay thank you c:
jimthompson5910 (jim_thompson5910):
no problem
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