please help all i did was x+5=0 subtract 5 from both sides and get x=-5
@jhonyy9 @baru @ace-n-it
y<x+5
stop do you know the difference between an inequality line and an equal line
you have got x=-5 for y=0
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do you know this table how can using it ?
@latinC yes a little bit and why is something wrong? i thought x=-5
x=-5 is right bc. than will be y=0
then what do i do @latinC
remember this y = mx + b
5 is your b value and the start of your line
since x doesn't have any numbers we know that you have a slop of 1x
so plot your first point at (0,5)
what are the pairs isnt it like (0,-5) and (5,0)??
Alright I am going to put this again: Just draw a slope as you normally would with the y-intercept being 5. The slope given to you is one. Since the symbol is Less than and NOT equal to, draw the line you used to graph the slope as a dotted line. In equalities you are going to have to shade n a portion of a graph depending on the sign that is given to you. If it is a less than sign you shade everything under the line while it is a greater than sign you shade in everything that is above the line however you will draw a dotted line for both. In an inequality where it is either less than or equal to/greater than or equal to you may draw a solid line. In this inequality, since the symbol is less than everything below the line drawn should be shaded in.
so i draw a line firs at (0,5) and then (5,0) ??
If those are points on the line, then yes. Make it a dashed line, NOT a solid line, to reflect the inequality symbol.
i tried that and even opposite both are wrong
your slop is positive meaning its going up not down, so (5,0) is wrong for it being a point on the line.
so i would do (0,5) first and then...
@latinC
so you have a slope of one so 1 in the x value and 1 in the y value would be (5+1, 0+1) for your new point
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