Mathematics
7 Online
OpenStudy (anonymous):
6th Grade Math
I will Fan and Medal the person who helps.
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RhondaSommer (rhondasommer):
Im here :D whats your question?
OpenStudy (anonymous):
I'll put the question up in a second. :)
RhondaSommer (rhondasommer):
:D okay :D
OpenStudy (anonymous):
OpenStudy (anonymous):
I think it is C.
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OpenStudy (anonymous):
But I have to pick two answers.
OpenStudy (er.mohd.amir):
just try cross multiply get II ans.
OpenStudy (baru):
you picked
\[r=\frac{14}{4}\]
can you do a simple algebraic re-arrangement by multiplying both sides by 4?
OpenStudy (baru):
both sides of the equation i mean
OpenStudy (anonymous):
What do you mean, sorry i'm really bad at math xd
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OpenStudy (baru):
we have
\[r=\frac{14}{4}\]
multiply the left and the right side of the equation by 4.
what do you get?
OpenStudy (anonymous):
56 and 16? o-o
OpenStudy (anonymous):
Because I multiplied 14 and 4..? Is that what I'm supposed to do? xD
OpenStudy (baru):
multiply both sides of
\[r=\frac{14}{4}\] by 4
we get
\[4 \times r=\frac{14 \times 4}{4}\]
OpenStudy (baru):
can you simplify that
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OpenStudy (anonymous):
Ohhhhhhhhhhhh
OpenStudy (anonymous):
probably
OpenStudy (baru):
give it a try, what are you left with?
OpenStudy (anonymous):
I am left with = 7/2 = 3 1/2
OpenStudy (baru):
can you do this
\[\frac{4}{4} = ?\]
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OpenStudy (anonymous):
yeah, 1
OpenStudy (baru):
lets look at the right side
\[ \frac{14 \times 4}{4}\]
it is the same as
\[ 14 \times \frac{ 4}{4}\]
so
\[ 14 \times \frac{ 4}{4}=?\]
OpenStudy (anonymous):
It is 14.
OpenStudy (anonymous):
14*4/4=14?
OpenStudy (baru):
yes!
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OpenStudy (anonymous):
So is that my answer? xD
OpenStudy (baru):
so the right side of
\[4 \times r=\frac{14 \times 4}{4}\]
becomes just 14
leaving us with
\[4 \times r=14\]
OpenStudy (baru):
does that look like any of your options?
OpenStudy (anonymous):
Um, no can you check my options?
OpenStudy (baru):
well,
i'll just tell you that it does look like one of your options.
you will have to look it up :)
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OpenStudy (anonymous):
I'll just go with A and D, thanks for the help.