What is the area found under the curve of y=sin(x/2), x0.

Question

What is the area found under the curve of y=sin(x/2), x>0.

bmk614 · Answer

A) 2
B) pi
C) 4
D) 2pi-1
E) 2pi

mathmale · Answer

For just one cycle of the sine function?  or?
While not strictly required, graphing this function and establishing the beginning and ending points of x for the area to be calculated might prove to be helpful to you.

Which methods have you learned for finding the area under a curve?  Have you studied definite integrals?  Have you estimated such areas using the Trapezoidal Rule or Simpson's Rule?

bmk614 · Answer

I have learned everything In AP Calculus AB... I am reviewing for the AP exam next week.

bmk614 · Answer

The the interval is between 0 and the first x-intercept

nnesha · Answer

$$area =\int\limits_{a}^{b} f(x) dx$$
hmm so first x-intercept at 2pi
[0, 2pi]
$$\int\limits_{0}^{2\pi}\sin(\frac{x}{2})dx$$e.e

nnesha · Answer

take the anti-derivative and then find F(b)-F(a)
here F represents the antiderivative

bmk614 · Answer

Thank you! I got the right answer!

nnesha · Answer

yw! :)