Question

Any help will be much appreciated :)
What are the points of discontinuity? Are they all removable? Equation in comments

Answer 1

y=
\[(x-5)\over(x^2-6x+5)\]

Answer 2

I found the points of discontinuity as x=1 and x=5

Answer 3

But how can I find if they're removable?

Answer 4

I think if it factors out it is a removabe discontinuity otherwise non removable

Answer 5

So then I need something where ab=6 and a+b=5 for the factoring of the denominator?

Answer 6

I should probably phrase that better" if says x-5 cancells in the numerator and denominator its removalbe

Answer 7

Ah ok

Answer 8

x=1 is non-removable jump or infinite discontinuity. You can evaluate it using limits at infinity if you wanted to.

Answer 9

So then the denominator factored is (x-1)(x+6) right?

Answer 10

Neither of them are removable because the denominator doesnt include (x-5)

Answer 11

Is that correct?

Answer 12

I dont think you factored the denominator correctly

Answer 13

(x-5)(x-1) is what I got for the denominator

Answer 14

Oh

Answer 15

I see that now, so then both are removable?

Answer 16

Since the (x-5) cancels out in the numerator?

Answer 17

only the x-5 is removable