On a hot day where the temperature is 32 deg celsius, the distance between two lamp post on the road is 30m as measured by a metal tape whose coefficient of linear expansion is hypothetically (50 x 10^-6)/deg celsius. If the tape gives its correct reading at 20 deg celsius, what is the actual distance between the lamp posts?
grabbed this from Wiki \(\dfrac{\Delta L}{L} = \alpha\Delta T\) and you know that \(\Delta L + L = 30 = L(\alpha \Delta T + 1 ) \) solve for L with \(\alpha = 50 \times 10^{-6}\) deg celsius and \(\Delta T = 12\)
We can solve it in little different way
We know the equation L=L0(1+alpha*theta)
If L=30m then Theta=32°c
Then the equation will b 30=L0(1+50*10^-6*32)
We will get another equation for 20°c
L=L0(1+50*10^-6*20)
Then divide equation 2 by equation 1
L=?
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