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Mathematics 8 Online
OpenStudy (korosh23):

SAT MATH LEVEL 2

OpenStudy (korosh23):

\[\frac{ 6 }{ x } + \frac{ 3 }{ y }=4 \]

OpenStudy (korosh23):

and

OpenStudy (korosh23):

\[\frac{ 3 }{ x }+\frac{ 6 }{ y }=\frac{ 7 }{2 }\]

OpenStudy (korosh23):

What is the value of xy? not x and y only xy

OpenStudy (korosh23):

for the first one: 6(1/x + 1/2y)=2/3

OpenStudy (latinc):

you're solving for xy right

OpenStudy (korosh23):

exactly

OpenStudy (latinc):

lets try this first equation --> y = 4/3 -2x and will input that in to the bottom equation to get 3/x + 6/(4/3-2x) = 2/3 and solve for x

OpenStudy (korosh23):

ok

OpenStudy (latinc):

= 7/2 not 2/3

OpenStudy (korosh23):

I don't understand a part

OpenStudy (korosh23):

3/x + 6/(4/3-2x) = 7/2 what is that 6 doing there?

OpenStudy (latinc):

are this two separate questions or are the equation part of the same question?

OpenStudy (korosh23):

the equations are part of the same question. I believe we have to use the method of substitution. I am not sure how.

OpenStudy (latinc):

give me sec

OpenStudy (korosh23):

ok

OpenStudy (latinc):

lets start from scratch, I messed up. the first equation is y = 4/3 -2x ---> we subtracted 6/x out and then divided by 3

OpenStudy (latinc):

now where back to the same equation the 6 is there because in your second equation y is under a 6

OpenStudy (korosh23):

wait a second, for the first equation, it must be 1/y = 4/3 - 2x

OpenStudy (korosh23):

you wrote y

OpenStudy (latinc):

divide by one again

OpenStudy (korosh23):

how is it possible? 1/1 . 1/y = 4/3 - 2x 1 at the bottom cancels out the 1 at the top. so 1/y = 4/3 - 2x

OpenStudy (latinc):

lets find a different way then

OpenStudy (korosh23):

I believe we have to divide both equations by a constant term which would be 3

OpenStudy (latinc):

(6/x+3/y=4) -2(3/x+6/y =7/2) this will elemenate the x value

OpenStudy (korosh23):

Ok wait, this is the answer key: the answer: 2/x and 1/y = 4/3 1/x + 2/y = 7/6 y = 3 and x = 2 xy=6

OpenStudy (latinc):

follow me we're on the right track

OpenStudy (korosh23):

Ok you have the answer. I know that at the begining we have to divide both equations by the value of 3. show me how you get y=3 and x=2

OpenStudy (latinc):

so from the equation you should get 1/y = 1/3 so then multiply by y and you'll have 1= y/3 so then multiply by 3 which will give you y = 3

OpenStudy (korosh23):

how did you get 1/y = 1/3

OpenStudy (latinc):

did you divide by the 9

OpenStudy (latinc):

-9/y = -3 ---> 1/y = 1/3 --> y = 3

OpenStudy (korosh23):

are saying all this from the answer key I provided you?

OpenStudy (korosh23):

or your own way

OpenStudy (latinc):

my own, I followed the equation

OpenStudy (latinc):

still gives the same answer

OpenStudy (korosh23):

you followed the equation from the answer key or the original equation?

OpenStudy (latinc):

original equation

OpenStudy (korosh23):

Ok, let me put all the steps into one. If I have further equestions. I will tag you here. Thanks a lot :)

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