Question

Express 16 = 2^x as a logarithmic equation.

log2x = 16
log162 = x
log216 = x
log16x = 2

Answer 1

\[y=b^x \implies \log_b(y)=x \\ \text{ where } b \in (0,1) \cup (1,\infty) , y>0\]

Answer 2

D ?

Answer 3

@freckles

Answer 4

can you compare y=b^x to your equation ?

Answer 5

and from it can you identify b and y?

Answer 6

and just plug in into the form that is equivalent that I have written above

Answer 7

base number is the one that ends up being the subscript of that log thing

Answer 8

mmm ;/

Answer 9

Look at what freckles gave you,
y=b^x

Then look at what you have,
16=2^x

All you have to do is identify y and b, then plug them into log_b (y) = x

Answer 10

y = 16
b = 2

log_2 (16) = x

Answer 11

so C ?

Answer 12

@jim_thompson5910

Answer 13

It's hard to tell, but \[\Large 16 = 2^x\] should turn into \[\Large \log_2(16) = x\]

Answer 14

@Gabylovesyou I gave you the medal because you were correct.