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Mathematics 18 Online
OpenStudy (anonymous):

I need a lot of help...plz :3

OpenStudy (anonymous):

OpenStudy (anonymous):

@jhonyy9 @sleepyjess

OpenStudy (anonymous):

@ikram002p @Elsa213

OpenStudy (reemii):

|dw:1461627222047:dw| A is somewhere on the dashed line.

OpenStudy (reemii):

|dw:1461627388871:dw|we kind of guess that there are two possibilities for A. Do you remember the formula for the distance between points (x,y) and (a,b) ?

OpenStudy (anonymous):

isnt the formula d=\[d=\sqrt{(x-a)^{2}+(y-b)}\]

OpenStudy (anonymous):

(y-b)^2*****

OpenStudy (reemii):

yes that's the one. The statement says: `the distance between point A and point B is 15 units.` How do you write that using the formula of the distance? (use the fact that A has x-coordinate -8 but unknown y-coordinate (call it 'y') ; B is (1,2))

OpenStudy (anonymous):

\[15=\sqrt{(1-(-18))^{2}+(2-y)^{2}}\]

OpenStudy (reemii):

it's (-8) instead of (-18), typo I guess. So: \[15=\sqrt{(1-(-8))^{2}+(2-y)^{2}}\] You want to find the \(y\) (or \(y\)'s). So, solve this for \(y\).

OpenStudy (anonymous):

I got 11.83....tbh i dont think thats right at all

OpenStudy (reemii):

you're right, it's not correct.. Step by step (you will see where you made a mistake): \(15 = \sqrt{(1-(-8))^{2}+(2-y)^{2}} \) \(\iff 225 = 9^2 + (2-y)^2 \) \(\iff 144 = (2-y)^2\) \(\iff (2-y) = 12 \) or \((2-y)=-12\) \(\iff y = -10\) or \(y = 14\).

OpenStudy (anonymous):

oooooooooooohhhh ok i see

OpenStudy (anonymous):

so the two possible coordinates would be (-8,-10) or (-8,14)

OpenStudy (anonymous):

right?

OpenStudy (reemii):

yes

OpenStudy (anonymous):

OMG you're the BESTTTT

OpenStudy (reemii):

you did well too

OpenStudy (anonymous):

When i was doing i kept getting confused on the "or" part

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