Question

A solution is made by dissolving 1.8 moles of sodium chloride (NaCl) in 0.198 kilograms of water. If the molal boiling point constant for water (Kb) is 0.51 °C/m, what would be the boiling point of this solution? Show all the steps taken to solve this problem.

[Hint: water boils at 100°C]

Answer 1

@sweetburger @Matt6288

Answer 2

Did you try to solve it?

Answer 3

yes, but I dont know where to start.

Answer 4

Can you tell me the formula and see if i do it right?

Answer 5

I think theres a formula 1 sec

Answer 6

how do you do that?

Answer 7

How do you do that

Answer 8

How do you solve?

Answer 9

Oh I get it now!

Answer 10

m is the molality
m = 1.8/0.198 = 9.091

Answer 11

are you replying?

Answer 12

is that the answer?

Answer 13

Is that the answer?

Answer 14

so this is how it suppose to look (1.8) (9.091 m) (0.51 °C/m) = 8.345538
+ 100 = The boiling point of the solution is 108.3°C

Answer 15

Anyways thats what I think it is