Question

What is the logarithmic form of the equation e^3x ≈ 3247?

log3x3247 = e
ln 3247 = 3x
3 logxe = 3247
ln 3x = 3247

Answer 1

log base 3 is written\(\ln(x)\)

Answer 2

I think @satellite73 meant to say `log base e is written ln(x)`

Answer 3

oh so its D

Answer 4

right ? @jim_thompson5910

Answer 5

Let's find out


Apply natural log to both sides
\[\Large e^{3x} \approx 3247\]
\[\Large \ln\left(e^{3x}\right) \approx \ln\left(3247\right)\]
\[\Large 3x*\ln\left(e\right) \approx \ln\left(3247\right)\]
\[\Large 3x*1 \approx \ln\left(3247\right)\]
\[\Large 3x \approx \ln\left(3247\right)\]
\[\Large \ln\left(3247\right) \approx 3x\]


I used the idea that `ln(e) = 1` and the idea that `ln(x^y) = y*ln(x)`

Answer 6

@jim_thompson5910 Thank youu