Question

http://prntscr.com/awx80z

Answer 1

any ideas? look how all the terms are different.

Answer 2

again u need to see
which can be taken out as common factor

Answer 3

none of them?

Answer 4

no

Answer 5

ill tell you that D is incorrect

Answer 6

ur incorrect @bexster

Answer 7

maybe 4b

Answer 8

how so?

Answer 9

like u know how they say like UR MOMS INCORRECT @bexster

Answer 10

is it 4b @rvc

Answer 11

see this :
\[\rm \color{red}{4ab}-7ax+\color{red}{8b}-14x=0~\\4b\color{blue}{(a+2)}-7x\color{blue}{(a+2)}=0\]

Answer 12

i did not see that

Answer 13

did u understand what i wrote?

Answer 14

where did that come from, the A+2

Answer 15

see carefully
u can get common terms

Answer 16

i don't see where it comes from

Answer 17

\(\large ☻☺+☻♥= ☻(☺+♥) \\ \text{this is factoring, } \\ \text{☻ was common from both terms and factored out.}\)

4ab + 8b
can be written as
\(4b \times a + 4b\times 2\)

Answer 18

<3 hartnn :)

Answer 19

and when you factor out 4b from both the terms,

'a' remains from 1st term
'2' remains from 2nd term

hence,
4b (a+2)
makes sense?

Answer 20

the smily face?

Answer 21

OH I SEE IT

Answer 22

yes it makes sense

Answer 23

gOOd

Answer 24

thanks y'all

Answer 25

how about -7ax -14x
?

Answer 26

we have to factor out -7x right

Answer 27

yes :)

Answer 28

so a would be left and nothing would be left in the second part

Answer 29

a would be left for first part

Answer 30

-7x factored from -14x will leave '2' from 2nd term :)

Answer 31

sorry I'm busy rn, and I see why it leaves 2 now @hartnn

Answer 32

cool,
so you now have

4b(a+2) -7x(a+2)

again,
(x+2) is common from both the terms and can be factored out!

Answer 33

wait i thought it was (a+2)

Answer 34

yes a+2

Answer 35

now we have (a+2) 4b-7?

Answer 36

or flipped around

Answer 37

7x
don't forget the brackets.

(a+2)(4b-7x)

which is same as
(4b-7x)(a+2)

Answer 38

yup!! THANK U GOKU @hartnn

Answer 39

good night everyone

Answer 40

The first rule of factoring is to try to factor a common factor out of all terms.
Here there isn't one.

When you see 4 terms, try factoring by grouping.
Factor a common factor out of the first two terms.
Then factor a common factor out of the last two terms.
Then factor out a common factor.

\(\large 4ab - 7ax + 8b - 14x\)

\(\large = a(4b - 7x) + 2(4b - 7x) \)

\(\large = (4b - 7x)(a + 2) \)

Answer 41

Good night.

Answer 42

thank you anyways! <3 @mathstudent55