Moment of inertia question.
We have a square plate whose moment of inertia is to be calculated about the axis passing through its one vertex and in the plane of paper making an angle of 15° with the horizontal line passing through centre of square plate.
@irishboy123
difficult to visualise?
First, I'll show that if an axis passes through the center of the square, then its moment of inertia is \(\frac{Ma^2}{24}\). Clearly, the two axes are kinda identical in a way, so their moments of inertia will be the same. They'll also add up to \(\frac{Ma^2}{12}\) because that's the perpendicular-axes theorem. So each would be \(\frac{Ma^2}{24}\). Now take your axis and find its distance from the center. Then apply the parallel-axis theorem to complete your problem. |dw:1461752681251:dw|
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