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Trigonometry
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r = 8sin(Theta). Write an equation in rectangular coordinates.
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what are x and y in polar?!?!
"Transform the polar equation to an equation in rectangular coordinates" is all it says ...
but everyone is telling me to use this formula: x = rcosθ y = rsinθ x² + y² = r²
yes that's right so \(r = 8 \sin( \theta)\) is the same as \(\sqrt{x^2 + y^2} = 8\dfrac{ y}{\sqrt{x^2 + y^2}}\)
Yes but I am not sure how to solve this..
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multiply each side by \(\sqrt{x^2 + y^2}\)
\[\sqrt{x^2 + y^2} * \sqrt{x^2 + y^2} = 8\dfrac{ y}{\sqrt{x^2 + y^2}}*\sqrt{x^2 + y^2} \]
??
\[\sqrt{x^2 + y^2} * \sqrt{x^2 + y^2} = x^2 + y^2 \] right?!
and \[\dfrac{ y}{\sqrt{x^2 + y^2}}*\sqrt{x^2 + y^2} = y\] yes?
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