Question

Help please? Will give fan and medal.

Assume that each of the n trials is independent and that p is the probability of success on a given trial. Use the binomial probability formula to find P(x).
n = 6
x = 3
p = 0.2

p(x) =
Thank you in advance :)

Answer 1

The binomial distribution formula: if there are n independent trials and the probability of success is p, then:
\[P(x)=\left(\begin{matrix}n \\ x\end{matrix}\right)p^x(1-p)^{1-x}\]

Answer 2

Soo, p(3) = (6/3)p^3)(1 - p)^1-3

Something like that? @Bobo-i-bo

Answer 3

yup ^_^

Answer 4

Okay, thank you!!!!

Answer 5

np! :)

Answer 6

(6/3) is not 6÷3, but \(C^6_3 = 20\).

Answer 7

Ahh, okay! How would I type that though?

Answer 8

(6/3) doesn't look like anything but 6÷3.
You can just use (6C3) for example.
Do you know the formula for this quantity?

Answer 9

Alrighty, thank you :)
Um, not really, no.

Answer 10

http://www.mathwords.com/c/combination_formula.htm

Answer 11

^ yup

Answer 12

Thank you guys :)

Answer 13

I applied the formula.

(6C3) = 6*5*4*3/3*2*1*0 = 0

Am I right?