I have no idea how to solve this question. "Find the work done by a 10 pound force acting in the direction (1, 2) in moving an object 3 feet from (0, 0) to (3, 0). "
\[F*dCos(\phi) = Work\]
where phi is the angle between the applied force and direction the object is moving.
I'm assuming that the applied force is being applied horizontally. if it were at an angle we would need to only consider the x component of the force since the object moves horizontally. well that's a different case I guess. |dw:1461725058230:dw| \[3~feet*(\frac{ 0.38m}{ft }) = 1.14~meters \] \[\phi = 0~degrees \] our applied force is 10 pounds, that needs to be in kg, and also force is in Newtons \[N = kg~\frac{ m }{ s^{2} }\] 10 pounds = 4.5kg \[4.5kg*9.8\frac{ m }{ s^{2} }*(1.14m)*Cos(0^{o}) = +50.3J\]
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