Question

Hard as pie

Answer 1

(n ^3)^3 · (n ^4)^5

Answer 2

lol og copi me

Answer 3

OG nuu i said pie

Answer 4

\[(x^a)^b= x^{a \cdot b}\]\[x^m +x^n\] when multiply same base, add exponents

Answer 5

okayso remember \[(x^a)^b=x^{a*b}\]

Answer 6

dang it they beat me to it ;p

Answer 7

the exponent represents how many times we should multiply the base by itself
\[x^1 * x^1 * x^1=x^3\]
for your question first multiply the inner and outer exponents and then add them p.

Answer 8

OG then add the exponents

Answer 9

\[(n ^3)^3 · (n ^4)^5\]
\[(n ^3)^3 = n^9\] \[(n ^4)^5 = n^{20}\]
\[n^9 + n ^{20} = n ^{29}\]
@AloneS

Answer 10

Thanks Kendric<3

Answer 11

Your welcome. Glad I could help :)

Answer 12

you should not write \(n^9 + n ^{20} = n ^{29}\) since this is not true.

write...

\[n^9 \times n ^{20} =n^{9+20}= n ^{29}\]

Answer 13

True, my mistake. Thanks @Zarkon