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Hard as pie
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(n ^3)^3 · (n ^4)^5
lol og copi me
OG nuu i said pie
\[(x^a)^b= x^{a \cdot b}\]\[x^m +x^n\] when multiply same base, add exponents
okayso remember \[(x^a)^b=x^{a*b}\]
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dang it they beat me to it ;p
the exponent represents how many times we should multiply the base by itself \[x^1 * x^1 * x^1=x^3\] for your question first multiply the inner and outer exponents and then add them p.
OG then add the exponents
\[(n ^3)^3 · (n ^4)^5\] \[(n ^3)^3 = n^9\] \[(n ^4)^5 = n^{20}\] \[n^9 + n ^{20} = n ^{29}\] @AloneS
Thanks Kendric<3
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Your welcome. Glad I could help :)
you should not write \(n^9 + n ^{20} = n ^{29}\) since this is not true. write... \[n^9 \times n ^{20} =n^{9+20}= n ^{29}\]
True, my mistake. Thanks @Zarkon
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