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Mathematics 16 Online
zarkam21 (zarkam21):

Help

OpenStudy (ebonygotthejuice):

yes?

zarkam21 (zarkam21):

OpenStudy (anonymous):

LP = 12-3 Then use Pythagoras theorem to find height Then apply the formula to find the area of the quadrilateral

OpenStudy (ebonygotthejuice):

what are your choices?

OpenStudy (anonymous):

Area of LMNO is A = L x h I think you don't have to minus 12-3 to get LP though. NO I don't think so

zarkam21 (zarkam21):

I don't have any choices

OpenStudy (john_es):

If you cut the triangle of the left and put it in the right you will a rectangle. So, as @DelTaVsPi said, you need to find the height ot the triangle because this will be the height of the rectangle. You must use the Pythagoras theorem, so,\[5^2=3^2+h^2\] where h represents the height. So you will have \[h=4\]. Now you have the base, b=12, and the height, h=4, so the area is\[S=b\times h=48\]

zarkam21 (zarkam21):

So 48?

OpenStudy (john_es):

Yes, do you understand the answer?

OpenStudy (john_es):

Remember that the units are square units.

zarkam21 (zarkam21):

Yes, I understand

OpenStudy (john_es):

Perfect ;)

OpenStudy (anonymous):

Nice work!

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