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OpenStudy (ebonygotthejuice):
yes?
zarkam21 (zarkam21):
OpenStudy (anonymous):
LP = 12-3
Then use Pythagoras theorem to find height
Then apply the formula to find the area of the quadrilateral
OpenStudy (ebonygotthejuice):
what are your choices?
OpenStudy (anonymous):
Area of LMNO is A = L x h
I think you don't have to minus 12-3 to get LP though. NO I don't think so
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zarkam21 (zarkam21):
I don't have any choices
OpenStudy (john_es):
If you cut the triangle of the left and put it in the right you will a rectangle. So, as @DelTaVsPi said, you need to find the height ot the triangle because this will be the height of the rectangle. You must use the Pythagoras theorem, so,\[5^2=3^2+h^2\] where h represents the height. So you will have \[h=4\]. Now you have the base, b=12, and the height, h=4, so the area is\[S=b\times h=48\]
zarkam21 (zarkam21):
So 48?
OpenStudy (john_es):
Yes, do you understand the answer?
OpenStudy (john_es):
Remember that the units are square units.
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