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Chemistry 15 Online
OpenStudy (18jonea):

Which element decreases its oxidation number in the following reaction? I2 +2KCl →2KI + Cl2 iodine chlorine potassium No element decreases its oxidation number. @sweetburger @zale101

OpenStudy (18jonea):

b? or d?

OpenStudy (18jonea):

@Zale101

OpenStudy (zale101):

I2 +2KCl →2KI +Cl2 What is the oxidation state in I2? What is the Oxidation state of Cl in KCl? What is the oxidation state in Cl2? What is the Oxidation state of I in KI?

OpenStudy (18jonea):

oxidation no. of I in I2 = 0 oxidation no. of K in KCl = +1 oxidation no. of Cl in KCl = -1 oxidation no. of I in KI = -1 oxidation no. of K in KI = +1 oxidation no. of Cl in Cl2 = 0

OpenStudy (zale101):

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OpenStudy (18jonea):

so iodine is the answer

OpenStudy (zale101):

By comparing Cl with I, which is reduced and which is oxidized?

OpenStudy (zale101):

the more negative the charge is the more electrons it has.

OpenStudy (18jonea):

iodine decreases it oxidation

OpenStudy (18jonea):

@Zale101

OpenStudy (zale101):

Iodine is being reduced and Cl is being oxidized

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