Question

How do I solve this series like these?

Answer 1

\[\sum_{k=1}^{425}(9k-3219)\]

Answer 2

see its forming an arithmetic
series

Answer 3

Find the 1st and Last terms using the formula, add them together and divide by 2 (take the average of the first and last terms) then multiply the amount of terms 424 in this case.

Answer 4

first term -3210
second -3201
third -3192

Answer 5

@jojokiw3 as @owikbenstan told just plug k = 1
u will get first term and k = 425 u wil get last term
and
\[S_n = \frac{ n }{ 2 }(a_1 + a_n)\]

Answer 6

-553350

Answer 7

\[\sum_{k=1}^{n} k=\frac{n(n+1)}{2} \\ \sum_{k=1}^{n} c= c \cdot n\]
you can also use these

Answer 8

@jojokiw3 yup
@owikbenstan it should be 425