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Mathematics 17 Online
OpenStudy (trisarahtops):

Write the definite integral for the summation:

OpenStudy (trisarahtops):

satellite73 (satellite73):

what do get if you put \(k=0\)?

OpenStudy (trisarahtops):

you mean? \[\sum_{k=0}^{n}\]

OpenStudy (trisarahtops):

@satellite73

satellite73 (satellite73):

i just meant what do you get if you replace k by 0 that will give you the lower limit of integration

satellite73 (satellite73):

the function itself should be pretty clear, since the exponent is 2, the integrand is \(x^2\)

OpenStudy (trisarahtops):

uh are you saying I must integrate x^2?

satellite73 (satellite73):

yes, \(x^2\) is the integrand

OpenStudy (trisarahtops):

isn't that x^3/3 (sorry if that's wrong I suck at math)

OpenStudy (john_es):

x^3/3 is the result of the integral. But the problem ask for the integrand, the term inside the integral. So the answer is what @satellite73 said. The integral with x^2 as integrand.

OpenStudy (trisarahtops):

oohh welll then I know the answer is either A B or D then

OpenStudy (john_es):

And the low limit with 0, as you see before.

OpenStudy (john_es):

You also know the low limit, by the reasons from before.

OpenStudy (john_es):

So, what is the answer?

OpenStudy (trisarahtops):

A

OpenStudy (john_es):

Wait, I think there is a problem with the limit.

OpenStudy (trisarahtops):

what the problem?

OpenStudy (john_es):

No, there is no problem. It is all ok, just I wanted to recheck.

OpenStudy (john_es):

A is the correct one.

OpenStudy (trisarahtops):

oh alright. Thanks again :)

OpenStudy (john_es):

You're welcome.

OpenStudy (john_es):

Hey, I found an error!!

OpenStudy (john_es):

Just, the infinite sum is not the same as the integral in A. It is not the answer A.

OpenStudy (john_es):

When you put k=0, the low limit is 1. So the good one, must have the low limit 1. It cannot be as k/n is just an infinitesimal. So it is C.

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