Write the definite integral for the summation:
what do get if you put \(k=0\)?
you mean? \[\sum_{k=0}^{n}\]
@satellite73
i just meant what do you get if you replace k by 0 that will give you the lower limit of integration
the function itself should be pretty clear, since the exponent is 2, the integrand is \(x^2\)
uh are you saying I must integrate x^2?
yes, \(x^2\) is the integrand
isn't that x^3/3 (sorry if that's wrong I suck at math)
x^3/3 is the result of the integral. But the problem ask for the integrand, the term inside the integral. So the answer is what @satellite73 said. The integral with x^2 as integrand.
oohh welll then I know the answer is either A B or D then
And the low limit with 0, as you see before.
You also know the low limit, by the reasons from before.
So, what is the answer?
A
Wait, I think there is a problem with the limit.
what the problem?
No, there is no problem. It is all ok, just I wanted to recheck.
A is the correct one.
oh alright. Thanks again :)
You're welcome.
Hey, I found an error!!
Just, the infinite sum is not the same as the integral in A. It is not the answer A.
When you put k=0, the low limit is 1. So the good one, must have the low limit 1. It cannot be as k/n is just an infinitesimal. So it is C.
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