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Solve for x
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\[\frac{ x }{ 2 } +1=\sqrt{3}\]
I got \[2\sqrt{3}\]
\[x=2(\sqrt{3}-1)\]
I guess if you multiply both sides by 2, you can get similar \[x+1=2\sqrt{3}\]
Uhh i dont' have those choices /:
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Well if u multiply both sides by 2 u get X+2=2sqrt3
Is avina's there?
yes mr Rapper.. x=2(3√−1) is the correct one.
What choices do they give you?
2√3 - 2 -2√3 - 2 -2√3 - 3
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distribute avina's answer
It's as @avinaysingh27 said above. \[\frac x2 + 1= \sqrt3 \iff \frac x2 = \sqrt3 - 1 \iff x = 2(\sqrt3 - 1) = 2\sqrt3 -\dotsb\]
It's ur first answer choice
can i have some help if i help u
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