Which of the following is the correct expansion of the binomial (x + y)6? x6 + 6x5y + 15x4y2 + 20x3y3 + 15x2y4 + 6xy5 + y6 x6 + 155y + 6x4y2 + 20x3y3 + 6x2y4 + 15xy5 + y6 x6 + 6x5y5 + 15x4y4 + 20x3y3 + 15x2y2 + 6xy1 + y6 x6 + 6x5y + 20x4y2 + 15x3y3 + 20x2y4 + 6xy5 + y6
Do you remember the binomial expansion?
And do you know the Pascal triangle?
uh no i dont
like i know it but i don't remember it
Ok. The binomial expansion tell you this, for example, for the the 2 and 3 powers, \[(x+y)^2=x^2+2xy+y^2\] \[(x+y)^3=x^3+3x^2y+3xy^2+y^3\]
what
Do you see how it goes?
no :(
You can do the same thing with the sixth power, \[(x+y)^6=x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6\]
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The way to obtain this is just to multply, as @BPDlkeme567 says, \[(x+y)(x+y)(x+y)(x+y)(x+y)(x+y)\]
can you not multiply (x + y)(x+y)?
no ;-;
Okay so we need to start there
c:
Yes, it is better the way @BPDlkeme567 says.
that is known as the difference of two squares. i.e x^2 + y^2
so, (x + y)(x- -y) = x^2 + y^2
hey human calculator @John_ES , can you take over and teach binomial theorem?
and polynomial identities
@tinalikescats it is actually based on a very simple idea, invented by the chines (forget that people call it Pascal's triangle), but have a look on wikipedia at Pascal's triangle.
wot
Pascals triangle starts with 1, next two numbers must be put below this, which is the sum of the previous numbers, but since there is only 1 previous number the two numbers under this are 1
oh, sorry, this might seem irrelevant, but these are the co-efficients of the mathematical expressions
are you there?
x6 + 6x5y + 15x4y2 + 20x3y3 + 15x2y4 + 6xy5 + y6
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