Can someone please help me with the problem below
Is there some more data? The radius of the front and back tires?
yes, ill send it right now
Well, the graph you were trying is correct. You need this distance. For the front tire, the radius is 12/2=6 inches. You know that part of the height is 6 inches,but you still don't know part of the height.
The part you don't know is the part that have the angle 30 there.
But you can calculate this height using what you probably know about triangles and the sine, \[height=R\cdot\sin(30)\]
So, the total height is \[h=6+6\cdot\sin30=6+3=9\ \ \text{inches}\]
In the formula that I wrote, R is the radius of the tire.
okay so the height would ben 9 inches ?
For the (a), yes.
okay
For the (b) use the same formula, but with R=6/3=2 inches. So, \[h=R+R\sin(30)=2+2/2=3 \ \ \text{inches}\]
okay thank you
You're welcome.
where did you get the 2 from ?
There is two of the, one for the R=2, and the other from here, \[\sin(30)=1/2 \]
I got 4.5
Oh, sorry, that was my mistake. R=6/2=3
So I did 3*sin(30)=1.5+3=4.5
\[h=R+Rsin(30)=3+3/2=3+1.5=4.5\]
okay thank you
Join our real-time social learning platform and learn together with your friends!