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Mathematics 21 Online
OpenStudy (wintersuntime):

Can someone please help me with the problem below

OpenStudy (wintersuntime):

OpenStudy (john_es):

Is there some more data? The radius of the front and back tires?

OpenStudy (wintersuntime):

yes, ill send it right now

OpenStudy (wintersuntime):

OpenStudy (john_es):

Well, the graph you were trying is correct. You need this distance. For the front tire, the radius is 12/2=6 inches. You know that part of the height is 6 inches,but you still don't know part of the height.

OpenStudy (john_es):

The part you don't know is the part that have the angle 30 there.

OpenStudy (john_es):

But you can calculate this height using what you probably know about triangles and the sine, \[height=R\cdot\sin(30)\]

OpenStudy (john_es):

So, the total height is \[h=6+6\cdot\sin30=6+3=9\ \ \text{inches}\]

OpenStudy (john_es):

In the formula that I wrote, R is the radius of the tire.

OpenStudy (wintersuntime):

okay so the height would ben 9 inches ?

OpenStudy (john_es):

For the (a), yes.

OpenStudy (wintersuntime):

okay

OpenStudy (john_es):

For the (b) use the same formula, but with R=6/3=2 inches. So, \[h=R+R\sin(30)=2+2/2=3 \ \ \text{inches}\]

OpenStudy (wintersuntime):

okay thank you

OpenStudy (john_es):

You're welcome.

OpenStudy (wintersuntime):

where did you get the 2 from ?

OpenStudy (john_es):

There is two of the, one for the R=2, and the other from here, \[\sin(30)=1/2 \]

OpenStudy (wintersuntime):

I got 4.5

OpenStudy (john_es):

Oh, sorry, that was my mistake. R=6/2=3

OpenStudy (wintersuntime):

So I did 3*sin(30)=1.5+3=4.5

OpenStudy (john_es):

\[h=R+Rsin(30)=3+3/2=3+1.5=4.5\]

OpenStudy (wintersuntime):

okay thank you

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