Find the sum of a finite geometric sequence from n = 1 to n = 7, using the expression −4(6)^n − 1. 111,325 526 782 -223,948
\(\large a_n = -4 (6)^{n-1}\) The sum of 'n' terms of an Geometric series is given by: \(\Large S_n = a_1 \dfrac{r^n-1}{r-1}\) where a1 is the first term = ..? r = common ratio = ...?
n = number of terms = 1 to 7 = 7
if you can find a1 and r from \(a_n\) then you just plug those in the formula and you'll get the sum
i'm not very good at this... can you help me?
i'll try :) In, \(\Large a_n = a_1 r^{n-1}\) the 1st term is a_1 and the common ratio is 'r'
you can also check this tutorial out: http://openstudy.com/study#/updates/503bb2a0e4b007f9003103b0
thank you!
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