What is the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of 0.94? Round your answer to the nearest tenth of a percent. A. 73.3% B. 58.1% C. 34.9% D. 90.9%
@Aveline
Check your table, specifically the probability distribution table. http://www.thestudentroom.co.uk/attachment.php?attachmentid=134337&d=1330530156 This one. Anyway, first look at the probability for a z score of .94, there's a 0.8264 probability of it being less than .94. -1.32 is the next value, the trick here is to turn the negative into a positive and 1-x it, x being the probability obtained. 1-.9066=0.0934 Look at the graph, to get the answer, just 0.8264-0.0934=0.733 A, the answer is, 73.3%
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