Question

fan+medal see pic

Answer 1

factor everything completely

Answer 2

Yep like calculus said factor first then you should be able to cancel some things.

Answer 3

this is your question and we are trying to help you answer it.

Answer 4

Because no one is supposed to give the answer in openstudy.

Answer 5

It is your work and YOU do it yourself.

Answer 6

we are here to guide you through the problem not give you answers... Read the policies if you are not familiar with them...

Answer 7

It is cheating if you get the answer by it self.

Answer 8

k i already factored it what should i do next

Answer 9

cancel out the terms that look identical. but cancel the ones that are like diagonal to each other.

for example

Answer 10

i got x-2/x^3(x+7)^2(x-3)^2

Answer 11

i don’t get it

Answer 12

what should i do to find the quotient

Answer 13

so for the quadratic ones (\(ax^2 + bx + c\)), those are the ones that can be factored by grouping. for the rest you need to find the GCF and take it out

Answer 14

ya i still don’t get it

Answer 15

do you know how to factor?

Answer 16

for instance, i will do the first fraction for you as a guide.
\[\frac{ x^2 - 4 }{ x^3 + 7x^2 } = \frac{ (x+2)(x-2) }{ x^2(x + 7) }\]

Answer 17

http://www.purplemath.com/modules/factquad.htm

Answer 18

i factored it and got x-2/x^3(x+7)^2(x-3)^2

Answer 19

notice that (x+2)(x-2)= x^2 - 4
and x^2(x+7) = x^3 + 7x^2

Answer 20

so its b?

Answer 21

why do you think it's b?

Answer 22

actually i think it might be c

Answer 23

don't use a calculator you can do this on paper...

Answer 24

let's check
this is the expression in factored form
\[\frac{ (x-2)(x+2) }{ x^2(x + 7) } \times \frac{ (x-3)(x+7) }{ x(x+2)(x-3) } \]

Answer 25

ya

Answer 26

do you understand how i got all of this?

Answer 27

yeah

Answer 28

so its c?

Answer 29

after canceling the terms out you should get:
\[\frac{ (x-2) }{ x^3 }\]

so yes it's C