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Mathematics 7 Online
OpenStudy (pphalke):

how do you graph 2x+10=0 its asking to graph by plotting points

OpenStudy (xguardians):

Well, with the information you gave, there is only one point you can solve for. Solve for X 2x = -10 x = -5 (-5,0) What is the original equation?

OpenStudy (pphalke):

what i gave you is the original equation 2x+10=0

OpenStudy (pphalke):

@xGuardians

OpenStudy (xguardians):

That is not an equation of a line, you need y in there. y = 2x + 10?

OpenStudy (pphalke):

here is the problem

OpenStudy (john_es):

Then it is a vertical line.

OpenStudy (xguardians):

@John_ES is correct, my bad. It would be a vertical line at x = -5.

OpenStudy (john_es):

But is strange that there is no "y" there. Anyways, you can solve for x, \[x=-5\] So this is a vertical line in x=-5.

OpenStudy (xguardians):

Therefore you can plot the points (5,x) Where x = any value from negative infinity to positive infinity.

Directrix (directrix):

For the two points, the x-coordinate must be -5. The y can be anything because there are no restrictions on y. (-5, 0 ) and (-5, 2) will do.

Directrix (directrix):

Or (-5, any number you like) for the graph of x = -5

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