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OpenStudy (trisarahtops):
Find the area or the region bounded by the curves y = x3 and y = 9x.
0
10.13
40.50
20.25
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OpenStudy (trisarahtops):
I have graph the functions
OpenStudy (trisarahtops):
they intersect at (0,0)
jimthompson5910 (jim_thompson5910):
Graph of the two functions
jimthompson5910 (jim_thompson5910):
the regions you want are in blue
jimthompson5910 (jim_thompson5910):
sorry I mixed up my color coding. Not sure how that happened
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jimthompson5910 (jim_thompson5910):
where else do the graphs cross @Trisarahtops ?
OpenStudy (trisarahtops):
oh I see at (3,27)
jimthompson5910 (jim_thompson5910):
where else?
OpenStudy (trisarahtops):
(-3,-27)
jimthompson5910 (jim_thompson5910):
the blue region is in 2 symmetric pieces. To find the area of the whole blue region, find the area of the upper half, then double it
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jimthompson5910 (jim_thompson5910):
f(x) = 9x
g(x) = x^3
\[\Large \text{area of upper half} = \int_{0}^{3}\left[f(x) - g(x)\right]dx\]
jimthompson5910 (jim_thompson5910):
since f(x) is the upper function on the interval from x = 0 to x = 3
OpenStudy (trisarahtops):
I got 20.25. And doubled would be 40.5 @jim_thompson5910
jimthompson5910 (jim_thompson5910):
40.5 is the correct final answer
OpenStudy (trisarahtops):
Thank you
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jimthompson5910 (jim_thompson5910):
no problem
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