Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (darkigloo):

How do I find the value of the convergent series?

OpenStudy (darkigloo):

\[\sum_{n=1}^{\infty} \frac{ 1 }{ n(n+6)}\]

OpenStudy (freckles):

i would try partial fractions

OpenStudy (freckles):

and see if the series telescopes

OpenStudy (darkigloo):

im not sure how to do that.. :(

OpenStudy (freckles):

hmm... that is the only way I know... you sure you guys haven't talked about telescoping series?

OpenStudy (darkigloo):

i don't think i've learned about that

OpenStudy (freckles):

what have you guys mentioned in class

OpenStudy (darkigloo):

the topic is divergence and integral test

OpenStudy (freckles):

but those can't use to find the value of the series

OpenStudy (darkigloo):

oh...

OpenStudy (freckles):

do you know at least how to write your fraction as a sum of partial fractions ?

OpenStudy (darkigloo):

ok, i have 20 more min to do my online hw so can I show you another problem that might be easier?

OpenStudy (freckles):

i guess... so i guess that means you haven't done partial fractions here? Like you might remember them using them to ingrate certain things...

OpenStudy (freckles):

for example \[\frac{1}{n(n+6)}=\frac{A}{n}+\frac{B}{n+6}\] and you would combine the fractions on the right to find A and B

OpenStudy (darkigloo):

Test each of the following series for convergence by the Integral Test. If the integral test cannot be applied to the series, enter NA.\[\sum_{n=1}^{\infty}\frac{ n+5 }{ (-4)^n}\] ∑n=1∞n+5(−4)n

OpenStudy (freckles):

The integral test says: Suppose that f(n) is continuous, positive, and decreasing function on the interval [1,inf) then \[\int\limits_k^ \infty f(x) dx \text{ converges } \implies \sum_{n=k}^{\infty} f(n) \text{ converges } \\ \int\limits_k^\infty f(x) dx \text{ diverges } \implies \sum_{n=k}^{\infty} f(n) \text{ diverges }\] do you think that we satisfy the hypothesis part of this test ?

OpenStudy (freckles):

\[f(x)=\frac{x+5}{(-4)^{x}} \\ \text{ is this continuous on } [1,\infty) ? \\ \text{ is this positive on } [1,\infty)? \\ \text{ does this decrease on } [1,\infty)?\]

OpenStudy (darkigloo):

its decreasing, continuous, but not positive?

OpenStudy (darkigloo):

increasing

OpenStudy (freckles):

it is also not continuous for example at x=1/2 the denominator is not defined over real numbers but anyways we just need it to fail at least one of those 3 things to rule out the integral test and you definitely got that it wasn't completely positive on [1,inf)

OpenStudy (darkigloo):

ahh ok.

OpenStudy (darkigloo):

that's it?

OpenStudy (freckles):

it is your question :p It says use the integral test if it can be applied. If it cannot be applied then say NA.

OpenStudy (freckles):

was there suppose to be more to the question? because that is all I see...

OpenStudy (freckles):

ratio test might work here but we cannot use the integral test because it didn't meet the conditions to apply the integral test

OpenStudy (freckles):

or i mean alternating series test

OpenStudy (darkigloo):

ok thank you !

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!