What is the equation in point-slope form of the line passing through (-3, -4) and (0, 2)?
WILL GET MEDAL
find the slope of the line first using the equation below. Pick one point to be \((x_1,y_1)\) and the other is \((x_2,y_2)\) and plug in the numbers \[m=\frac{ y_2-y_1 }{ x_2-x_1 }\]
okay so i did \[y=2-(-4)\div0-(-3)\]
and got 6/3
@peachpi
yes, so that's 2.
now plug into the point-slope formula \[y-y_1=m(x-x_1)\] m is the slope you just found you can use the same point you used above for (x1, y1)
y - 8) = 2(x - 3) (y + 3) = -2(x + 4) (y - 2) = -2(x + 4) (y + 4) = 2(x + 3) these are the choices
@peachpi
y - (-4) = 2(x - (-3)) y + 4 = 2(x + 3)
Okay, i think i got it now thanks!! @peachpi
do you have time fore another one? it will be my last! @peachpi
ok
How do you find the rate of change for this question? @peachpi
Use the slope equation we used before. Since they want the rate of change from 1 to 4, use those x and y values. At x = 1, y = 3, so that point is (1, 3). At x = 4, y = 0, so that point is (4, 0) \[\frac{ 0-3 }{ 4-1 }\]
it says -1!
so it would then be 0-3/4-(-1)?
then after that it would then be... -3/5
@peachpi
it's -1
the 1 in your denominator is positive
oh my bad i was reading the question rather than what you wrote! @peachpi
Okay thank you for help i understand noww!! It was correct!
you're welcome
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