Question

Write the equation in polar form.
3x-4y-10=0

Answer 1

Do you know what the polar form of an equation is?

Answer 2

yes I do

Answer 3

Post it, what have you tried so far?

Answer 4

when I found out that p=2, and currently struggling to get \[\phi\]

Answer 5

as of right now I got Arctan 3/-4

Answer 6

Oh My I cant do this sorry XDD

Answer 7

oh, Its ok

Answer 8

Okay, so:
\[3x-4y-10=0\]\[3x-4y=10\]\[3r Cos\theta -4r Sin\theta = 10\]
Now just solve for r and you're done.

Answer 9

oh wow, I was taught a different way using arctan

Answer 10

\[r(3Cos\theta - 4Sin\theta)=10\]\[r=\frac{10}{3Cos\theta-4Sin\theta}\]

Answer 11

Hmm I have been out of college for a while, so I don't remember what I was taught - I was following this link to solve this though: http://www.ck12.org/book/CK-12-Trigonometry-Concepts/section/6.6/ (look at example 3)

Answer 12

ok, thanks anyway

Answer 13

BACON CONFETTI!

Answer 14

lol

Answer 15

remember what x and y in polar form are? \(x=r\cos{\theta}\text{ and }y=r\sin{\theta}\)

Answer 16

yep

Answer 17

Okay so you have the equation \(3x-4y-10=0\) which becomes \(3r\cos{\theta}-4r\sin{\theta}-10=0\)

Answer 18

... I don't know what I'm doing ; - ;

Answer 19

I'm studying for a test that involves these things too and my brain's fried x_x

Answer 20

just outta curiosity, what Grade?

Answer 21

yeah, I was taught using arctan, but I think your way would also work

Answer 22

what class grade, or what grade I have in the course? o_o

Answer 23

yeah

Answer 24

class grade

Answer 25

College freshman, second semester.

Answer 26

no wonder it seems like you know everything, lol

Answer 27

I do not know everything... xD but thank you for the compliment :P

Answer 28

ok so back to the question, whats next lol

Answer 29

*brain died*

Answer 30

WAIT NO

Answer 31

XD

Answer 32

its ok, I'm assuming you got your own test to prepare for, Thanks

Answer 33

Okay so hahrom was right... \(3x-4y-10=0\rightarrow3r\cos{\theta}-4r\sin{\theta}=10\)
Then you can factor r out of the left side: \(r(3\cos{\theta}-4\sin{\theta})=10\)

Answer 34

ok, I'm having trouble getting \[\phi\]

Answer 35

then to get r you divide the other stuff from 10: \(r=\frac{10}{3\cos{\theta}-4\sin{\theta}}\)

Answer 36

Uh... I think to get \(\theta\) you would need to get the \(\arctan{\frac{y}{x}}\)?
Arctangent is also \(\tan^{-1}{\theta}\)

Answer 37

HOLD ON I NEED TO ANSWER MY OWN QUESTION @ - @

Answer 38

ok

Answer 39

i used \[xcos \theta+ysin \theta-p=0\]

Answer 40

@Noobsteriscastic

Answer 41

Is it solved?

Answer 42

nope

Answer 43

He needs help finding the angle \(\theta\) but I have no idea how to do that, my brain is fried from my own polar conversions lol @Noobsteriscastic

Answer 44

yeah what she said

Answer 45

can you help @Noobsteriscastic?

Answer 46

ok so you have 3x-4y=20
use x=rcos(theta), y=rsin(theta)

Answer 47

ok

Answer 48

I'm just gonna call it a day, Thanks @Noobsteriscastic ,@bahrom7893, and @kittiwitti1 once again

Answer 49

You need to convert (x,y) to (r, theta)
first of all find x, find y. To find x put y=0. To find y, put x=0.
then use \[x^2 + y^2 =r^2 \]
to find r
and theta=arctan(y/x) to find find theta.

Answer 50

sorry I just can't think at the moment Thanks anyways, I appreciate it

Answer 51

ok well. how about you take a break and come back later?

Answer 52

the problem is that once I take that break, I'll knock out 'till tomorrow, lol

Answer 53

lol dude, you can't learn if you don't want to.

Answer 54

ik, XD

Answer 55

Thanks anyway @Noobsteriscastic