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OpenStudy (erikaxx):
help me in homogeneous equation
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OpenStudy (erikaxx):
determine in each exercise whether or not the equation/function is homogeneous. if it is homogeneous, state the degree of teh function
OpenStudy (erikaxx):
\[1. y` = \frac{ 2y^4+x^4 }{ xy^3}\]
OpenStudy (erikaxx):
\[2. y` = \frac{ (x^2+y) }{ x^3 }\]
OpenStudy (erikaxx):
\[3. y` = \frac{ x^2+y }{ xy }\]
OpenStudy (erikaxx):
4. \[y`= \frac{ x^2 }{ y }\]
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OpenStudy (erikaxx):
\[5. y` = \frac{ y }{ x + \sqrt{xy} }\]
OpenStudy (erikaxx):
@kittiwitti1
ganeshie8 (ganeshie8):
Hi
ganeshie8 (ganeshie8):
Look at the right side of the given equation.
```
Replace x by kx
Replace y by ky
```
what do you get ?
OpenStudy (erikaxx):
\[= \frac{ ky^4 +kx^4 }{ kxky^3}\]
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OpenStudy (erikaxx):
@ganeshie8 hey
ganeshie8 (ganeshie8):
simplify the fraction a bit by factoring out k's
ganeshie8 (ganeshie8):
also you have it wrong
OpenStudy (erikaxx):
\[k(y^4+x^4)/k(xy^3)\]
ganeshie8 (ganeshie8):
x^4
replacing x by kx gives you (kx)^4
not just kx^4
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ganeshie8 (ganeshie8):
\(\large y' = \frac{ 2y^4+x^4 }{ xy^3} \)
replace y by ky and x by kx
\(\large y` = \frac{ 2(ky)^4+(kx)^4 }{ kx(ky)^3} \)
ganeshie8 (ganeshie8):
use the property
\[(ab)^n=a^nb^n\]
OpenStudy (erikaxx):
\[y`` = \frac{ 2(ky)^5+(kx)^5 }{ kx(ky)^4}\]
ganeshie8 (ganeshie8):
??
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