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Mathematics 20 Online
OpenStudy (erikaxx):

help me in homogeneous equation

OpenStudy (erikaxx):

determine in each exercise whether or not the equation/function is homogeneous. if it is homogeneous, state the degree of teh function

OpenStudy (erikaxx):

\[1. y` = \frac{ 2y^4+x^4 }{ xy^3}\]

OpenStudy (erikaxx):

\[2. y` = \frac{ (x^2+y) }{ x^3 }\]

OpenStudy (erikaxx):

\[3. y` = \frac{ x^2+y }{ xy }\]

OpenStudy (erikaxx):

4. \[y`= \frac{ x^2 }{ y }\]

OpenStudy (erikaxx):

\[5. y` = \frac{ y }{ x + \sqrt{xy} }\]

OpenStudy (erikaxx):

@kittiwitti1

ganeshie8 (ganeshie8):

Hi

ganeshie8 (ganeshie8):

Look at the right side of the given equation. ``` Replace x by kx Replace y by ky ``` what do you get ?

OpenStudy (erikaxx):

\[= \frac{ ky^4 +kx^4 }{ kxky^3}\]

OpenStudy (erikaxx):

@ganeshie8 hey

ganeshie8 (ganeshie8):

simplify the fraction a bit by factoring out k's

ganeshie8 (ganeshie8):

also you have it wrong

OpenStudy (erikaxx):

\[k(y^4+x^4)/k(xy^3)\]

ganeshie8 (ganeshie8):

x^4 replacing x by kx gives you (kx)^4 not just kx^4

ganeshie8 (ganeshie8):

\(\large y' = \frac{ 2y^4+x^4 }{ xy^3} \) replace y by ky and x by kx \(\large y` = \frac{ 2(ky)^4+(kx)^4 }{ kx(ky)^3} \)

ganeshie8 (ganeshie8):

use the property \[(ab)^n=a^nb^n\]

OpenStudy (erikaxx):

\[y`` = \frac{ 2(ky)^5+(kx)^5 }{ kx(ky)^4}\]

ganeshie8 (ganeshie8):

??

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