what is y=3(x+1)^2+9 in standard form?
sorry i was trying to do my other problems
you're good(:
wouldn't you get x^2 and 1
Yes(: so now what would you do to simplify this equation?
opps sorry idk why i put +9 it is -7
so would you add the +1 to the -7?
\[3(x+1)^{2} + 9= 3(x+1)(x+1) + 9\]
shoot yes @Photon336 is right
disregard what I said
yeah, it's easy to get tripped up on that
so you would actually get \[3(x+1)(x+1) = 3(x^2 + 1x + 2x + 1) = \color{green}{3(x^2 + 2x + 1)}\]
sorry i meant to say 3(x^2 + 1x + 1x + 1)
im so confused rn
sorry
first you need to foil (x+1)(x+1)
Haha okay so (x+1)^2 is also (x+1)(x+1)
so it's \[y=3(x+1)(x+1)-7\]
and then foil like @Photon336 said earlier
what is foil?
Okay so first you multiply the (F) first terms of each expression. in this case, it would be x and x. Then you multiply the (O) Outer two terms of the binomial which in this case is x and 1. After that, you do the same for the (I) Inner two terms, x and 1, and the (L) last two terms. Once you find what you got for F, O, I, and L, you add those together and simplify.
@liljj1421 come back!(:
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