Anyone want to help a brother out?
Write -2x+4y=9 in polar form using the polar form of a linear equation.
all I need help in is getting phi
equation: \(-2x+4y=9\) x and y in polar form: \(x=r\cos{\theta}\) and \(y=r\sin{\theta}\) so you get \(-2x+4y=9\rightarrow-2r\cos{\theta}+4r\sin{\theta}=9\)
What are x and y in polar form? In other words, how would you express x and y in terms of r (radius) and theta (angle)?
sorry, I should've mentioned I already found p, I'm just not sure when to add or subtract 180 or 360
...I don't know what \(p\) stands for, sorry
well it is used in the equation \[p=rcos(\theta-\phi)\]
Hmm. My professor did not teach us this method...
all I am having trouble is when I get the Arctan, I don't know when to add or subtract 180 or 360 respectively to its quadrant location
I am sorry, I've never learned these methods before. I could help you, but I don't know if it will produce the right answer. :(
its ok, either way I know the answer, but don't know how to get it
Well, maybe @ganeshie8 can help you ^-^;
ok thanks
do you have any questions about my response and did you even look at the link I sent before re-posting?
yeah I actually have
I just wanted to know when to add or subtract 180 or 360 @triciaal
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