A couple days ago some guy helped me figure this project out and i got these answers http://imgur.com/MUowbp7 but he aint online and i need help now so i need to know how he got these distances between the buildings because he never told me. Can you help?

Question

tylermckinney16 · Answer

@skullpatrol

skullpatrol · Answer

Do you know how to use the Pythagorean theorem?

tylermckinney16 · Answer

no i dont. I forget.

skullpatrol · Answer

Which distances do you want to find?

tylermckinney16 · Answer

all of them i half to explain how i got these. http://imgur.com/MUowbp7 but idk how i did cause my friend did it for me but didnt explain how he got them.

skullpatrol · Answer

Do you have the original question?

tylermckinney16 · Answer

yeah hold on

tylermckinney16 · Answer

Its in this  cityplanningproject1.docx

tylermckinney16 · Answer

@skullpatrol

tylermckinney16 · Answer

@mathstudent55

tylermckinney16 · Answer

@ScarlettFarra2000

scarlettfarra2000 · Answer

Sorry @TylerMckinney16 my school laptop wouldn't left me see the site

tylermckinney16 · Answer

@welshfella

welshfella · Answer

It seems a good layout and conforms with the requiremts

welshfella · Answer

the 2 schools are the same distance from the police and fire departments 
Take the elementary scholo located at  (-12,0)    the -12 refers to the x cordinate - its 12 units left of the origin (0,0)

this is 12 + 10 = 22  units form thr recreation center  which is at (10,0)

If we move verically up 10 units from here we arrive at the fire station at (10,12)

and if we move down from (10,0)  10 units we get the police station at (10 , -12)  so we see that requirement is met .

SDimilarly the high school is same distance from fire and police.

welshfella · Answer

to find the exact distance   we use the pythagoras theorem

=  square root [(-12-10)^2 + (10- 0)^2)]

tylermckinney16 · Answer

Is that what i put for it? @welshfella

welshfella · Answer

well you mentioned distances  Thats the way to work them out 

If the buildings ar on the same horizontal and vertical line  the distances are easy to find.

remember (10,12)  means x  (horizontal) value is 10 and  y 9vertical) valuye is  12,

so the distance between (-12,0) and (-9,0)  is difference of x values only - in this case 
its 12 - 8 = 4   (ignore the negatives)

and distance betwene (0,4) and (0,8) is 8-4 = 4

tylermckinney16 · Answer

Awesome so thats what i put :)?

welshfella · Answer

* horizontal OR vertical line , i should have said.

welshfella · Answer

Yea I guess so.

welshfella · Answer

dont forget each unit is a kilometer

tylermckinney16 · Answer

Ok thanks you will get a medal.