The chord AC of parabola y^2=4x subtends 90° angle at points B and D on parabola.Of A,B,C, and D are represented by t1,t2,t3,t4 then
|t2t4-t1t3| =?
@ganeshie8
Could you draw the parabola and label the points/lengths ?
I just got two equations which are:- (t1+t2)(t2+t3)=-4 (t1+t4)(t3+t4)=-4
I don't understand the question; The way you have phrased it is very confusing
Instead of the word "Of" in the question it is "if".
Sorry I don't get why you want to label the points by two names. Something seems to be wrong
It would help if you take a screenshot of entire question and attach
t1,t2,t3,t4 are the parameters of A,B,C AND D.
Do you mean t1, t2, t3, t4 are the "position vectors" of the points A, B, C, D ?
Like the point A is (at1^2, 2at1) , we have assigned it a parametric term (t1) and likwise it is for the rest of them.
Did you get it?
y^2 = 4x parametric form would be (t^2, 2t)
Are you saying A = (t1^2, 2t1) B = (t2^2, 2t2) C = (t3^2, 2t3) D = (t4^2, 2t4) ?
Yup that's how he assigned the paramaters.
I'm guessing you would find the gradients of AB, AD, BC and CD
She* And yes ganeshie sir that's what i mean.
then you should end up with the equations (t1+t2)(t2+t3) = -1 (t1+t4)(t4+t3) = -1 right ?
Why so? We have a slope of any chord to be 2/t1+t2 for a parabola.
okay -4 on the right hand side lets see where to go from here
We didn't use the value of a of parabola in coming to this conclusion though.I think second equation must result from use of that.
@parthkohli
@thomas5267
I don't even understand the question. I am too tired now anyway.
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