Question

find he position of a particle moving along a coordinate line that satisfies the given conditions

a(t)= 2sint - cost

s(0) = 6
v(0)=0

Answer 1

a = acceleration (second derivative)
s = position? I'm guessing?
V = velocity (first derivative)

Answer 2

hmm is that the same for anti derivatives ?

Answer 3

\[a=\frac{ d^2s }{ dt^2 }\]
\[v=\frac{ ds }{ dt }\]
\[\frac{ d^2s }{ dt^2 }=2\sin t-\cos t\]
integrate and find the value of constant from the given condition.
Again integrate and find the value of constant from the given condition.