Assuming the energy of a single pulse is delivered to a volume of the cornea about 1 mm3, and assuming the pulses are delivered so quickly that the energy deposited has no time to flow out of that volume, how many pulses are required to raise the temperature of that volume from 20°C to 100°C? (Assume that the cornea has a heat capacity similar to that of water.)

Question

mos1635 · Answer

there is something mising here....

syone · Answer

4.19 Joules raise the temperature of 1 gram of water by 1 degree C.
The density of water is 1000 kg / cubic meter. Therefore it is assumed that 1 mm^3 of cornea weighs 10^-3 grams.
4.19 mJ raise the temperature of 10^-3 g of cornea by 1 degree C.
80 * 4.19 mJ raise the temperature of 10^-3 g of cornea by 80 degrees C.
Each pulse delivers 0.5 mJ, therefore the required number of pulses is
80×4.190.5=670 pulses

mos1635 · Answer

"Each pulse delivers 0.5 mJ" that i was missing !

physics_dude99 · Answer

$$Q = mc \Delta T$$ $$m =  \rho*V$$