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Mathematics 18 Online
OpenStudy (ishipdestiel):

Find the midpoint of diagonal BD. Figure ABCD is shown. A is at negative 3, 2. B is at 0, 6. C is at 6, 6. D is at 3, 2. (1, 3.5) (1.5, 4) (2, 3.5) (2, 4)

OpenStudy (ishipdestiel):

OpenStudy (mathmale):

You know the x- and y- coordinates of B and D. Please look up the "midpoint formula" and apply it to this situation, substituting these coordinates into the formula as appropriate. (Google "midpoint formula.")

OpenStudy (ishipdestiel):

I know the midpoint formula but im not sure what goes where

OpenStudy (ishipdestiel):

M= (x1+x2, y1+y2) 2 2

OpenStudy (welshfella):

B is the point (0,6) - x is 0 and y is 6 D is the point (3,2) do you get that?

OpenStudy (ishipdestiel):

Okay give me a minute to work it out

OpenStudy (ishipdestiel):

wait no, im still confused, can you give me what the coordinates are for x1,x2 and y1 and y2 Please I will work it out

OpenStudy (welshfella):

(x1,y1) = ( 0,6)

OpenStudy (welshfella):

(x2,y2) = (3,2)

OpenStudy (ishipdestiel):

Okay so M=(0+3, 6+2) 2 2 3/2 + 4 = 4 3/2

OpenStudy (ishipdestiel):

I mean (3/2, 4)

OpenStudy (desmarie):

do you know what the midpoint formula is?

OpenStudy (ishipdestiel):

I have already worked it out above. could you check

OpenStudy (desmarie):

your answer was almost right it is suppose to be (-3/2, 2)

OpenStudy (ishipdestiel):

could you explain how you got this

OpenStudy (desmarie):

so x1 = 0, x2 = 3, y1 = 6, y2 = 2 then you just plug these values into the formula

OpenStudy (ishipdestiel):

I did this and got M=(0+3, 6+2) 2 2

OpenStudy (desmarie):

oh lol yeah you are right I was looking at the wrong thing sorry

OpenStudy (ishipdestiel):

Ok thank you could you check another problem

OpenStudy (desmarie):

sure tag me when you are done I will be right back

OpenStudy (ishipdestiel):

Thanks and its just like nameing the shape Quadrilateral ABCD has coordinates A (3, 5), B (5, 2), C (8, 4), D (6, 7). Quadrilateral ABCD is a rectangle, because opposite sides are congruent and adjacent sides are perpendicular square, because all four sides are congruent and adjacent sides are perpendicular parallelogram, because opposite sides are congruent and adjacent sides are not perpendicular rhombus, because all four sides are congruent and adjacent sides are not perpendicular

OpenStudy (mathstudent55):

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OpenStudy (mathstudent55):

Your graph is much better than mine, so look up the things I do in my graph on your graph because you'll get a more accurate look.

OpenStudy (mathstudent55):

The first thing we need to do is to see if any sides are congruent.

OpenStudy (mathstudent55):

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