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Find the derivative of f(x) = 5/x at x = -1.
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Hey Alex, recall a helpful exponent rule,\[\large\rm \frac{1}{x}=x^{-1}\]
Applying this rule will allow us to use our power rule for differentiation.
So this would be x^-5?
No but good guess.\[\large\rm \frac{5}{x}=5\cdot\frac{1}{x}\]
The 5 can just simply come down in front. And then you can apply the rule to the x-portion sitting next to it.
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Is it -1?
\[\large\rm f(x)=\frac5x\qquad\qquad\qquad\to\qquad\qquad\qquad f(x)=5x^{-1}\]Ok yes, good. That's how we bring the x up to the numerator, we apply a -1 power to it. Now it's ready for power rule. Remember how to do that?
-1 * 5 = -5?
I don't quite understand.
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