Question

Evaluate -b+sqrtb^2-4ac for the given values of a, b, and c. Write the result as a complex number.

Answer 1

\[-b+\sqrt{b^2-4ac}\]

a=1
b=-6
c=13

Answer 2

I got \[6+2i \sqrt{22}\]

and I'm nearly positive that it's correct, just wanted to see if you could double-check it since double negatives always throw me :)

Answer 3

i got \[-6+4i\]

Answer 4

\[\frac{ -(-6)\pm \sqrt{(-6)^2-4(1)(13)} }{ 2(1) } = \frac{ 6 \pm \sqrt{36-52} }{ 2 }\]
\[\frac{ 6\pm \sqrt{-16} }{ 2 } = \frac{ 6 \pm 4i }{ 2 }= 3 \pm 2i = 3 + 2i, 3 - 2i\]

Answer 5

my bad 6 plus and minus 4i, unless it's asking you to solve the whole quadratic equation with 2a in the denominator, in which case zenmo is correct. If it is just askin -b+...., then the answer is 6+4i and 6-4i,

Answer 6

So my answer is correct?

Answer 7

@jhonyy9 Hey mind looking at this question and checking to see if my answer is correct?

Answer 8

@Kainui Hey, would you mind looking at this question and checking to see if my answer is correct?

Answer 9

a=1
b=-6
c=13

-b + sqrt(b^2 -4ac)

-(-6) +sqrt(36-4*13*1

6 +sqrt(36-52)

6+sqrt(-16)

6+4i

you have got this ?

Answer 10

I see, so it's 6+4i and not 6+2i sqrt 22?

Answer 11

6+4i is correct sure

Answer 12

Thank you Jhonyy!

Answer 13

was my pleasure and anytime you like or i m here online

bye bye

Answer 14

and good luck