Using the table for many repetitions of the experiment of tossing a coin 10 times, what is the mean number of heads in 50 repetitions of this experiment and 500 repetitions, and which of these sample means is closer to the population mean? Number of Heads 0 1 2 3 4 5 6 7 8 9 10 In 50 Repetitions 0 0 1 5 9 16 10 6 2 1 0 In 200 Repetitions 0 2 8 22 38 55 41 24 9 1 0 In 500 Repetitions 2 5 24 57 111 111 110 56 21 3 0 In 1,000 Repetitions 1 8 43 117 207 248 203 121 45 6 1 x bar equals 4.8, 5.03; 50 repetitions are closer to the population mean x bar equals 4.9, 4.99; 50 repetition
can you help!?!? @John_ES
I am reading and thinking about it ;)
please ill give you a medal!
im timed on the question but please can you try to help me @John_ES
Ok, it was easier than I was thinking at first.
oh okay
You should calculate the mean using the definition, \[\overline{x}=\sum\frac{x_if_i}{N}\]For the first case, you have \[\overline{x}=4.94\] And the second, \[\overline{x}=5.2\] Then, you can choose your answer because the mean for the experiment is \[\mu=np=10\cdot0.5=5\] So you must choose the x that is closer to this value.
is C the closest?
When I say the first case, I mean, the 50 repetitions. The second case is the 500 repetitions.
Yes, C is the closest.
Do you understand how I calculated the means?
no i dont sorry
this question is kinda the same equation right?
Using the table, I use the formula, \[\overline{x}=\sum\frac{x_if_i}{N}\] In the case of 50 repetitionis, N=50. x_i is the number of heads, and f_i is the number of times you obtain this heads. So for N=50, using the table you have, \[\overline{x}=(2*1 + 3*5 + 4*9 + 5*16 + 6*10 + 7*6 + 8*2 + 9)/50=5.2\]And for N=500, you have, \[\overline{x}=(2*0 + 1*5 + 2*24 + 3*57 + 4*111 + 5*111 + 6*110 + 7*56 + 8*21 + 9*3)/500=4.94\]
ohhhh yeah i get it now how you found the mean
Yes, is somewhat different. In the problem the formulas you should use are written.
yeah so how do i solve it then, idk what numbers to use
First, calculate SD, using the highest and lowest amounts. Tell me your result.
so $200-$140 right?
i mean $200 - $75
Yes, and then divide by 6, using the formula they provide.
125/6 = 20.8
Ok. Now apply the second formula using N=500, the number of students.
1.86
Perfect! you have your answer.
oh wow thank you and this last one im sorry
Tell me.
i really wanna understand this so i can do the rest on my own
so i added everything to the formula and got 0.017
\[2*\sqrt{.72(1-.72/2500}\]
Yes, that's perfect!
i did it right?!?!?
no way ! thank god
However, remember that in this case p=0.28 1-p=0.72
In the formula that doesn't matter. But you should remember that the problem stays that the proportion of yes is "p", and the proportion of "no" is q=1-p.
ohhhh okay yeah i understand
thank you so much
you really did help
You're welcome.
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