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Mathematics 16 Online
OpenStudy (marcoreus11):

How do I do these problems?

OpenStudy (marcoreus11):

Problems

OpenStudy (john_es):

Do you know the formula for the volume of a cone?

OpenStudy (marcoreus11):

yeah

OpenStudy (john_es):

Remember that the oblique cone has the same formula as the straight cone.

OpenStudy (marcoreus11):

i know but i dont know how to do the pi thing

OpenStudy (marcoreus11):

the base is 4 right?

OpenStudy (john_es):

I will do it for the first case. In the first case, h=4 ft R=4/2=2 ft Then \[V=\frac{\pi r^2 h}{3}=\frac{\pi 2^2\cdot2}{3}=\frac{8}{3}\pi=2.67\pi\ ft^3\approx 3 \ ft^3\]

OpenStudy (marcoreus11):

why 2? as base

OpenStudy (john_es):

Sorry, I forgot the pi in the last step. \[3\pi \ ft^3\]

OpenStudy (john_es):

Well, the formula I have used is this, \[V=\frac{\pi r^2 h}{3}\] In the problem you have a circular base whose radius is the half of the diameter. They give you the diameter, 4. So your radius is r=4/2=2. Ok?

OpenStudy (marcoreus11):

i thought the formula for volume of a cone is 1/3 x b x h

OpenStudy (john_es):

Exactly, but in the "b" it is not the "base" it is the "area of the base", ok?

OpenStudy (john_es):

In this case, the b, I mean, the area of the base is, \[b=\pi r^2\]

OpenStudy (marcoreus11):

oh so whenever a formula asks for base it the are so i would find the area formula for the shape right?

OpenStudy (marcoreus11):

base=area?

OpenStudy (john_es):

In this formula, yes. But remember, the area of the base.

OpenStudy (marcoreus11):

okay

OpenStudy (john_es):

Do the same for the other problems, and you will obtain the answer easily.

OpenStudy (marcoreus11):

i did it alreay

OpenStudy (john_es):

Except in the last one, where they give you the radius and not the diameter. In that case put r= 2 m, directly.

OpenStudy (john_es):

Ok, perfect.

OpenStudy (marcoreus11):

thank you

OpenStudy (john_es):

You're welcome.

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