Find the area of the triangle. Round your answer to the nearest tenth, if necessary. https://api.agilixbuzz.com/Resz/~Ey6YBAAAAAgn2YAMGLV7AA.5zHw-8j3BbxCE1XsQH0SjB/19809088,B84/Assets/assessmentimages/alg%202%20pt%202%20u2l9%207.jpg 90.4 in.2 140.3 in.2 70.1 in.2 80.8 in.2
You should find the heifht (using the angle) and the base, then apply the formula for the area: \[A=\frac{b\cdot h}{2}\] Or you can find the last side you don't know and apply the Heron's formula.
actually 70.1?
@John_ES
@jhonyy9
@Abhisar
No, the correct answer is anther one.
Have you find the side you don't have?
70.1
?
No, this is a wrong answer.
Ok, I will write how I would do it. Ok?
ok
First, I will calculate the side we don't have, using the cos theorem. As we have a triangle, we have 3 sides, I will name each of one this way, a=9 c=18 b= is the unknown The cos theorem, says that, \[c^2=a^2+b^2-2ba\cos(C)\] where C=60 degrees.
As we don't know b, we find its value, using the above relation and we find that, \[b=20.725\ \ in\]
Now we can apply the Heron's formula for the area that says that, \[A=\sqrt{s(s-a)(s-b)(s-c)}\] where s is the semiperimeter: \[s=\frac{a+b+c}{2}\]So using this we have, \[A=80.8\ \ in^2\]
so thats the answer?
That's the answer. You can apply the process to similar problems.
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