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~Rewards for everyone who helps~ Determine the value of K such that when f(x)=x^4+kx^3-3x-5 is divided by x-2, the reminder is -11.
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So i basically divided f(x) by x-2. and got the remainder of 8k-16. I then that the remainder equal -11, where I got k=3.375 Is this correct?
use the remainder theorem If the remainder is -11 when dividing by (x - 2) then f(2) = -11
so 2^4 + 2^3 * k - 3(2) - 5 = -11 solve for k.
@welshfella Oh I see. so I didn't really have to divide them at all?
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